Cosmology

A factor of three, and the flatness that prices every cure

The oldest stars in the Galaxy show a third of the lithium the first three minutes should have left. Three kinds of resolution have been offered, and the datum that rules on all three is not how much lithium is missing but how uniformly it is missing.

Assumes Nucleosynthesis, Energy transport and Spectra.

Three of the four light elements agree. Deuterium inverted through a nuclear network and the height of the second acoustic peak give the same baryon density to a few per cent; helium, once its flat curve is read as a species counter rather than as a baryometer, sits where it should. Then there is lithium.

A factor of 2.9, and the density that would remove it. The predicted ⁷Li abundance against the baryon density, with the halo-star measurement as a horizontal band and the microwave background's density as a vertical one. At η₁₀ = 6.13 the network gives 4.70e-10 and the stars show 1.60e-10, a factor of 2.94 — 0.47 in the logarithm, which is the number every proposed resolution has to produce. The obvious cure is drawn as the second marker: ⁷Li rises as η², so the density that would reproduce the observation is η₁₀ = 3.58, a third below the measured one. That is where the cure fails, and it fails on a different element. Deuterium falls as η^(−1.6), so at 3.58 the predicted D/H is 5.946e-5 against the 2.527e-5 measured in quasar absorbers — 2.35 times too much, and 114 times deuterium's own error bar. Helium, meanwhile, moves to 0.2445 and stays inside its measurement, because its curve is flat. The three light elements do not fail together, and that is what rules out a single wrong parameter: whatever is wrong is wrong about mass seven specifically.
Fig. 1 The predicted ⁷Li abundance against the baryon density, with the halo-star measurement as a horizontal band and the microwave background’s density as a vertical one. At η₁₀ = 6.13 the network gives 4.7 × 10⁻¹⁰ and the stars show 1.6 × 10⁻¹⁰: a factor of 2.94, or 0.47 in the logarithm, which is the number every proposed resolution has to produce. The obvious cure is the second marker — ⁷Li rises as η², so η₁₀ = 3.58 would fit the stars — and it fails on a different element. Deuterium at that density would be 5.9 × 10⁻⁵ against 2.5 measured, 114 times its own error bar, while helium moves to 0.2445 and stays inside its measurement because its curve is flat.

That figure disposes of the tidiest possibility before the essay begins. The light elements do not fail together, so nothing that moves the one free parameter can rescue them: whatever is wrong is wrong about mass number seven in particular. What remains are three kinds of resolution — the stars destroyed the lithium after it was made, the observation is not measuring what it is taken to measure, or the network that predicts the abundance is missing something — and the surprising thing about them is that the datum which prices all three is not the size of the discrepancy at all.

It is worth saying at the outset how unusual this failure is in its setting. Big-bang nucleosynthesis is the oldest quantitative prediction in cosmology and the one with the fewest adjustable parts: one free number, four abundances spanning nine orders of magnitude, and a reaction network whose rates were measured in accelerators for entirely unrelated reasons. Three of those four land where they should, and one of the three lands there from a measurement taken in a gas cloud twelve billion light years away. A subject with that much predictive success and one failure is in a different position from a subject with a general disagreement — the failure is localised, and a localised failure is either a mistake in one place or a discovery in one place.

The plateau, and what makes it a plateau

The measurement is a single absorption line at 6707.8 Å in the spectra of old, warm, metal-poor dwarf stars in the Galactic halo. Monique and François Spite found in 1982 that the abundance derived from it was the same in every such star they looked at, and the constancy was the discovery rather than the value.

Two decades of iron, and a lithium abundance that does not move. Lithium abundance on the astronomers' scale — A(Li) = 12 + log(Li/H) — against iron abundance for warm metal-poor dwarfs. The horizontal band is the Spite plateau, A(Li) = 2.20 with a scatter of about 0.06 dex, which is comparable to the measurement error and therefore consistent with no intrinsic scatter at all. The upper line is what big-bang nucleosynthesis predicts at the microwave background's baryon density, A(Li) = 2.67: 0.47 dex above the stars. The rising curve is what a production explanation would look like — lithium made by cosmic-ray spallation on interstellar carbon and oxygen accumulates as the Galaxy enriches, so it rises with iron, by 0.19 dex across this range — and the plateau does not do that, which is why the plateau has been read since 1982 as a floor rather than as a yield. That reading is what makes the discrepancy a problem. If the plateau were production, its height would carry no information about the first three minutes; because it is flat it is being read as the primordial value survived, and it is 3.0 times too small. What the flatness costs any stellar resolution is a matched condition: whatever destroyed the lithium destroyed the same fraction of it in every star drawn here, over two decades of metallicity, to within 0.06 dex.
Fig. 2 Lithium abundance on the astronomers’ scale against iron abundance for warm metal-poor dwarfs. The horizontal band is the plateau, A(Li) = 2.20 with a scatter of about 0.06 dex, comparable to the measurement error and therefore consistent with no intrinsic scatter at all. The upper line is what big-bang nucleosynthesis predicts at the microwave background’s density, A(Li) = 2.67. The rising curve is what a production explanation would look like — lithium made by cosmic-ray spallation on interstellar carbon and oxygen accumulates as the Galaxy enriches — and the plateau does not do that, which is why it has been read since 1982 as a floor rather than as a yield.

The flatness is doing two jobs at once and they pull in opposite directions. It is what licenses reading the plateau as primordial: an abundance that does not care how much iron a star has is not an abundance the Galaxy made, because everything the Galaxy makes tracks iron. And it is what makes the discrepancy hard to remove, because any process that removed lithium from these stars would have had to remove the same fraction from every one of them.

The reason lithium is unusual among the elements here is that the Galaxy really does make some. Cosmic-ray protons and alpha particles striking interstellar carbon, nitrogen and oxygen chip fragments off them, and a small share of those fragments are ⁶Li and ⁷Li — the same spallation process that makes beryllium and boron, neither of which is made in stars at all. That production scales with the amount of carbon and oxygen there is to hit, so it rises with metallicity, and it is visible in the disc stars: above about [Fe/H] = −1 the lithium abundance climbs away from the plateau and reaches roughly A(Li) = 3.3 in the young interstellar medium. The plateau is what is left when that rise is extrapolated down to a metallicity at which there was nothing to spall.

There is one place where the plateau is not flat, and it is the place a stellar explanation points to.

Where the plateau ends, and what its ending proves. The same lithium abundance against effective temperature rather than against metallicity, with temperature increasing to the left in the usual convention. Above about 6,000 K the abundance sits on the plateau at A(Li) = 2.20; below 5,900 K it collapses, by 1.9 dex at 5400 K on the model drawn. The cause is not in dispute: lithium burns at two and a half million kelvin, a cooler dwarf has a deeper convective envelope, and once the envelope reaches down to that temperature the surface lithium is circulated into it and destroyed. The curve is a logistic in T_eff with a stated width rather than a stellar model, and it is drawn because the shape is the argument. This is the evidence that stars do destroy lithium — visibly, at the level of a factor of a hundred — and it is simultaneously the evidence against destruction as the resolution. A process this steep in temperature cannot remove 0.47 dex uniformly from every star on the flat part, which is what a stellar explanation of the plateau's height requires. The two halves of the same figure say opposite things about the same mechanism, and that is why the problem has stood for forty years rather than being settled by pointing at the meltdown.
Fig. 3 The same abundance against effective temperature, increasing to the left. Above about 6,000 K the stars sit on the plateau; below 5,900 K the abundance collapses, by 1.9 dex at 5,400 K on the law drawn. The cause is not in dispute — lithium burns at two and a half million kelvin, a cooler dwarf has a deeper convective envelope, and once the envelope reaches that temperature the surface lithium is circulated down and destroyed. This is the evidence that stars do destroy lithium, visibly and by two orders of magnitude, and it is simultaneously the evidence against destruction as the resolution.

Both halves of that figure are about the same mechanism and they say opposite things. The meltdown proves that convective envelopes destroy lithium. The flat part, immediately beside it, proves that whatever destroyed 0.47 dex from the plateau stars did so without caring about the one variable the meltdown says controls the destruction.

The argument the second moment makes

The usual way to state this is qualitative: the plateau is too flat for a stellar explanation. It is worth making quantitative, because the numbers decide how much room there is rather than whether there is any.

The scatter a destruction law leaves, against the depletion it delivers. For a family of lithium-destruction laws, the star-to-star scatter each one produces plotted against the mean depletion it achieves, over dwarfs spread across the plateau's own temperature range of 6000–6500 K. The law is the same logistic in effective temperature the meltdown fixes, and the three curves differ only in its width: 105 K, 300 K, 900 K. The narrowest is the steepness the observed meltdown actually shows — 1.9 dex across roughly 400 K — and it is the one that fails. To remove the 0.47 dex the discrepancy requires, a law that steep has to put its threshold inside the plateau's own temperature range, so it strips the cool half and leaves the warm half untouched, and the scatter it leaves is 0.40 dex against the 0.06 the plateau shows. Widening the law fixes the scatter — at 900 K it is down to 0.058 dex — and a law that wide is no longer the law the meltdown measured. That is the whole difficulty with the stellar resolution, and it is a difficulty about a second moment rather than a first: the height of the plateau says how much lithium is missing, and its flatness says that whatever removed it did so without caring which star it was in. Nothing about convective envelopes is indifferent to effective temperature.
Fig. 4 For a family of destruction laws, the star-to-star scatter each produces against the mean depletion it delivers, over dwarfs spread across the plateau’s own temperature range of 6,000 to 6,500 K. The three curves differ only in the width of the logistic. The narrowest, 105 K, is the steepness the observed meltdown shows; to remove the 0.47 dex required it has to place its threshold inside the plateau’s own range, strips the cool half and leaves the warm half untouched, and leaves 0.40 dex of scatter against the 0.06 observed. Widening the law to 900 K brings the scatter down to 0.058, and a law that wide is no longer the law the meltdown measured.

The gap is a factor of about seven in the induced scatter, and it does not close by adjusting the threshold — the curves are drawn with the threshold already chosen, at every mean depletion, to be the one that delivers it. What a stellar resolution therefore needs is not a mechanism that destroys lithium; the meltdown supplies one of those. It needs a mechanism that destroys lithium without depending on effective temperature, which is to say without depending on convection, in stars whose only lithium-destroying machinery is convective.

The one serious candidate is thermohaline or rotational mixing driven by the molecular-weight gradient a hydrogen-burning core leaves behind — a slow circulation that is not the convective envelope and that has its own, much weaker, dependence on the star’s surface. Models of it can reach a few tenths of a dex with acceptable scatter. Getting the full 0.47 requires the mixing efficiency to be at the upper end of what the models allow, and the efficiency is a free parameter calibrated on other things. The situation is that the stellar resolution is not excluded and is not comfortable, which is roughly where it has sat for two decades.

There is a genuine piece of evidence in its favour, and it comes from the coolest and most metal-poor stars rather than from the plateau. Below about [Fe/H] = −2.8 the plateau develops a downturn and a scatter that it does not have above that metallicity — stars that ought to be the most pristine of all show less lithium and show a spread. That is not what a primordial floor does, and it is exactly what a destruction process that becomes efficient in a particular corner of the parameter space does. Whether the mechanism responsible there can be turned up enough to account for the whole plateau, without producing scatter on the flat part, is the question the models are arguing about; the existence of the downturn at least establishes that the plateau is not perfectly inert.

What makes the whole stellar route awkward in a way no single model addresses is a coincidence it has to swallow. The mechanism must remove 0.47 dex — and 0.47 dex is what is needed only because the microwave background measured the baryon density to be what it is. Before 2003 the density was not known independently, the predicted lithium was quoted over a range, and the plateau sat comfortably inside it. A stellar process that destroys precisely the amount a measurement made twenty years later would come to require is not impossible, but it is a coincidence, and the alternative resolutions do not have to explain it because they are tied to the same number.

The nucleus that has to be destroyed is not lithium

Before pricing the other two routes, one thing about the object of the exercise has to be corrected, because it changes what a mechanism has to do.

The lithium that is not made as lithium. The share of surviving mass-7 that is produced as ⁷Be rather than as ⁷Li, against the baryon density. Two channels make mass number seven. ³H(α,γ)⁷Li builds the lithium directly and dominates at low density, where the plasma is thin enough that the lithium is not immediately destroyed by ⁷Li(p,α)⁴He. ³He(α,γ)⁷Be builds beryllium instead, and beryllium has no proton-destruction channel available to it at these temperatures, so it survives — and then, months later, once the universe is cool enough for it to capture a bound electron, ⁷Be decays to ⁷Li with a half-life of 53 days. At the microwave background's density 95 per cent of the mass-7 that survives took the second route. The curve drawn is the standard logistic split, stated rather than integrated, and it is the one quantity in this figure that is a parameterisation rather than a calculation. What is not a parameterisation is the consequence, and it is what every proposed resolution has to reckon with: the object that has to be destroyed is a beryllium nucleus at 60 keV in a plasma with no bound electrons, not a lithium nucleus in a star. A mechanism that destroys lithium and leaves beryllium alone changes nothing at all.
Fig. 5 The share of surviving mass-7 produced as ⁷Be rather than as ⁷Li, against the baryon density. Two channels make mass number seven: ³H(α,γ)⁷Li builds lithium directly and dominates at low density, and ³He(α,γ)⁷Be builds beryllium instead. Beryllium has no proton-destruction channel at these temperatures, so it survives — and then, months later, once the universe is cool enough for it to capture a bound electron, decays to ⁷Li with a half-life of 53 days. At the microwave background’s density 92 per cent of the surviving mass-7 took the second route.

So the plateau’s lithium was, for the first several months of the universe’s existence, beryllium. A mechanism that destroys lithium during nucleosynthesis and leaves beryllium alone changes essentially nothing. And a mechanism that destroys lithium in stars is acting on the decay product, four hundred thousand years and one recombination later, which is the stellar route already discussed.

The reason the two channels split the way they do is a difference in what destroys the product rather than in what makes it. Lithium made directly has a proton-induced destruction channel, ⁷Li(p,α)⁴He, which is fast at nucleosynthesis temperatures and which the plasma has plenty of protons for; so direct lithium is made and immediately unmade, and only the fraction produced late enough to escape survives. Beryllium’s analogous channel, ⁷Be(p,γ)⁸B, runs into the fact that there is no stable nucleus at mass eight, so the product falls apart and the beryllium is effectively unmakeable-away. It survives untouched until the universe cools enough for it to hold onto an electron, which is at recombination, and then it decays. The whole of mass-7’s survival therefore turns on a nucleus that could not be destroyed because the thing it would have turned into does not exist.

That leaves the third kind of resolution, which acts on the beryllium during the interval before it decays. Everything in that class works the same way.

Neutrons are not selective

Destroying ⁷Be requires taking it out of the plasma, and the only lever available in a bath of photons and protons is a free neutron: ⁷Be(n,p)⁷Li converts it into lithium, and a proton then removes the lithium through ⁷Li(p,α)⁴He, which is fast. Every proposal in this class — a decaying massive particle, a hadronic injection, an annihilating relic — reduces to a supply of neutrons at the right epoch.

The neutrons that destroy the lithium also make deuterium. What a late injection of free neutrons does to the two abundances at once, drawn as a track through the plane they live in. Every proposal that removes mass-7 after nucleosynthesis has finished works the same way: ⁷Be(n,p)⁷Li converts the beryllium to lithium and a proton then removes it, so what is needed is neutrons. Neutrons are not selective. The share that finds a ⁷Be nucleus rather than a proton is the ratio of the two cross sections times the beryllium abundance — 38,000 barns against 0.332 barns, both proportional to 1/v so the ratio of thermal values is the ratio of rates, times 4.70e-10 — which comes to 5.38e-5. Every beryllium nucleus destroyed therefore costs about 18,600 deuterons made, and the deuterons survive, because at this epoch nothing is left that can burn them. Bringing ⁷Li down to the measured 1.60e-10 needs 9.41e-6 neutrons per hydrogen and leaves D/H at 3.453e-5, which is 37 per cent above the measured 2.527e-5 and 31 times its error bar. The shaded strip is what deuterium is measured to; the track leaves it long before the lithium arrives. This is not a bound on one model. It is a bound on the whole shape of resolution, because the branching ratio is atomic physics and no choice of particle changes it.
Fig. 6 What a late injection of free neutrons does to the two abundances at once. The share of injected neutrons that finds a ⁷Be nucleus rather than a proton is the ratio of two cross sections times the beryllium abundance — 38,000 barns against 0.332, both 1/v so the thermal ratio is the ratio of rates, times 4.7 × 10⁻¹⁰ — which comes to 5.4 × 10⁻⁵. Every beryllium nucleus destroyed costs about 18,600 deuterons made, and those deuterons survive, because at this epoch nothing is left to burn them. Bringing ⁷Li to the observed value needs 9.4 × 10⁻⁶ neutrons per hydrogen and leaves D/H 37 per cent above what is measured, thirty-one times its error bar.

That is the most decisive figure of the three routes, and its strength is that it does not depend on the model. The branching ratio is a ratio of two measured cross sections and an abundance, none of which a choice of particle can alter, so any mechanism that destroys mass-7 by neutron injection pays the same twenty thousand deuterons per nucleus. The deuterium measurement — a pair of absorption lines eighty-two kilometres a second apart — is what closes it, and it closes it by a wide margin rather than marginally.

There are cleverer versions. A particle that decays electromagnetically rather than hadronically photodissociates ⁷Be directly, without free neutrons, and pays in a different currency: the same photons dissociate deuterium as well, and because deuterium’s binding energy of 2.2 MeV is the lowest of any nucleus present, it goes first. The constraint reappears with the sign reversed and is if anything tighter. A particle that is negatively charged and binds to ⁷Be — a long-lived stau in some supersymmetric spectra — catalyses its destruction with no injection at all, by pulling the nuclear charge down and lowering the Coulomb barrier its destroyers have to cross. That is the one proposal in the class that is not obviously priced out, and it requires a specific new particle with a specific lifetime and a specific abundance, which is a large thing to buy for one number.

The shape of the whole class is worth extracting, because it recurs. A cure that acts on one species through a shared channel pays for the cure in every other species that uses the channel, and the price is fixed by the ratio of two rates rather than by the model. This collection meets the same structure in the neutrino count read off the helium abundance, where an exotic species cannot contribute to the expansion rate without also contributing to the helium — and in the recombination history, where anything that delays recombination to make one observable fit moves the sound horizon and breaks another. A single knob attached to two things is not a knob.

What is actually measured, and what it rests on

The observation behind A(Li) = 2.20 is a resonance doublet of neutral lithium at 6707.8 Å, and in a halo dwarf it is a feature about five per cent deep and a tenth of an ångström wide. Converting its equivalent width to an abundance needs the star’s effective temperature, its surface gravity, its metallicity and a model atmosphere, and the sensitivity is almost entirely to the first: the abundance derived scales with temperature at roughly 0.07 dex per 100 K.

That is the quiet load-bearing quantity in the whole subject. A systematic error of 200 K in the halo-dwarf temperature scale — which is not an outrageous error for stars at [Fe/H] = −3 whose colours are calibrated against much more metal-rich analogues — moves the plateau by 0.14 dex, or a third of the discrepancy. Successive temperature scales published since 1994 differ by rather more than that from one another. The scales have not moved in a direction that would close the gap, and the discrepancy has survived every one of them, but a reader should know that the second-most-likely resolution is a mundane one and that the field has been checking it for forty years for exactly this reason.

There are two further things about the line that are worth knowing before treating its equivalent width as an abundance. It is formed out of equilibrium: neutral lithium is a trace ionisation stage — the element is more than 99 per cent ionised in these atmospheres, because its ionisation potential is 5.4 eV against hydrogen’s 13.6 — so the abundance derived depends on the ionisation balance as well as on the temperature, and on the radiation field that sets it rather than on the local gas temperature alone. Corrections for that departure are computed, are of order 0.05 dex, and go in the direction of raising the derived abundance slightly. And the feature is a doublet whose components are 0.15 Å apart, unresolved in most spectra, so what is measured is a blend whose equivalent width is well defined even when its shape is not.

How much density each abundance is worth. The logarithmic slope d ln A / d ln η of each predicted abundance, measured by central difference on the same curves the abundances are read off rather than taken from the exponents in the fitting formulae. The slope is the exchange rate between a measurement and an inference: an abundance known to one per cent fixes the baryon density to one per cent divided by the modulus of this number. At the microwave background's density the four are ⁴He 0.04, D −1.60, ³He −0.60 and ⁷Li 2.00. Helium sits almost exactly on zero across the whole range, which is why it is drawn as a horizontal line in every abundance figure and why it counts neutrino species instead. Deuterium's −1.6 is the one the whole method rests on, and it is a statement about the reaction network: deuterium is the fragile intermediate every other product has to pass through, so raising the density burns more of it away. The uncomfortable line on the plot is lithium's, at 2.0: it is the steepest of the four, so ⁷Li would be the best baryometer in the set if its measured abundance agreed with its predicted one, and it is out by a factor of three.
Fig. 7 The logarithmic slope of each predicted abundance across a wider density range. Lithium’s is +2.00, the steepest of the four, so a per-cent measurement of ⁷Li would fix the baryon density better than the same measurement of deuterium. The exponent is a count: most of the mass-7 that survives is built by ³He(α,γ)⁷Be, a two-body reaction between two species whose abundances each rise with the density, so the product rises as the square. The awkwardness of that number is worth sitting with — the abundance nobody can reconcile is the one with the best leverage in the set.

The one that would have been most interesting

The remaining possibility is that the network is wrong: a nuclear reaction rate, measured in a laboratory at energies above the ones that matter and extrapolated down, is off by enough to change the mass-7 yield.

It has been looked for hard, because it would be the cheapest resolution available and because the relevant cross sections are genuinely difficult. ³He(α,γ)⁷Be is the production channel and would have to be roughly a factor of three smaller than measured; it is the same reaction that sets the solar neutrino flux from ⁷Be and ⁸B, and it is known to about five per cent from underground measurements at solar energies. A destruction channel large enough to matter — ⁷Be(d,p)2α was the best candidate — was measured directly and came out too small by an order of magnitude.

So the resolution that would have been most satisfying is the one most thoroughly closed. The remaining rate uncertainties in the whole network propagate to about a five per cent uncertainty in the predicted ⁷Li, against the factor of three that has to be explained. That closure is worth a moment, because it is the sort of result that reads as a negative and is not one: the reason a nuclear-rate resolution can be ruled out at all is that the rates were remeasured at the energies that matter, in underground accelerators built for solar-neutrino physics, by people who were not thinking about lithium. A prediction is only falsifiable to the extent that its inputs are independently known, and this one now is.

The deuterium burning rate against the expansion, at two baryon densities. The rate at which a deuteron is destroyed, divided by the expansion rate, against temperature. Temperature falls to the right, so the picture reads left to right as time, and the horizontal line at one is where the burning stops mattering: above it a deuteron is destroyed many times over before the universe doubles in size, below it the reaction has effectively ceased. The rate drawn is D(p,γ)³He at the NACRE parameterisation, multiplied by the free-proton density — three quarters of the baryons by number once ⁴He has taken the rest — and the expansion rate is the same 1.66√g* T²/mPl the freeze-out calculation raced the weak interactions against. The three curves differ in one number and one only: the baryons per photon, 3.58, 6.13 in units of 10⁻¹⁰. They are therefore vertical translations of each other, exactly in proportion to η, because the reaction is two-body and the expansion is not. That is the entire mechanism by which an abundance measures a density. A denser universe crosses the line later — 19.8 keV at η₁₀ = 3.58, 15.9 keV at η₁₀ = 6.13 — and every extra second below the crossing is deuterium that does not survive. What the figure does not do is predict the abundance itself: the residue depends on the whole reaction network and on the ⁷Be and ³He channels that feed back into it, and the curve the abundance is read off is a fit to that network rather than to this.
Fig. 8 The deuterium burning race at the density that would fix lithium and at the density everything else measures. The lower-density universe stops burning at 19.8 keV and the higher one at 15.9, a difference of about ninety minutes in when the network goes quiet, and that difference is the whole of why the two predict deuterium abundances differing by a factor of 2.35. The same interval that makes lithium fit makes deuterium wrong — the two elements are read off the same clock and cannot be set independently.

The isotope that turned out to be a line shape

There is a fourth episode, now closed, that is worth telling because of how it closed rather than because of what it claimed.

Between 2006 and 2010 several groups reported a detection of ⁶Li in halo dwarfs at about five per cent of the ⁷Li — a second plateau, at roughly a thousand times what big-bang nucleosynthesis predicts for that isotope, which the network makes only in traces because the ⁶Li channels are weak and its destruction by protons is fast. Nothing in standard physics makes that much ⁶Li at that metallicity, and the claim was taken seriously enough to generate a substantial theoretical literature about late-decaying particles producing it.

The detection was not a line. The two isotopes’ 6708 Å features are separated by 0.16 Å, which no spectrograph resolves in a star this faint, so the measurement was of a slight asymmetry in the blended profile: a ⁶Li component sitting a fifth of an ångström to the red would make the line’s red wing marginally deeper. The asymmetry was measured, at the level of a per cent of the line depth, and interpreted as isotopes.

What it was instead was convection. A stellar photosphere is a boiling surface: rising granules are hot, bright and blueshifted while sinking lanes are cool, dark and redshifted, and the resulting line is intrinsically asymmetric with a redward-leaning wing — the convective blueshift that shifts every line in a stellar spectrum and shifts each one differently. One-dimensional model atmospheres, which is what the ⁶Li analyses used, have no granulation in them at all and therefore predict a symmetric profile. Three-dimensional hydrodynamic models produce an asymmetry of very nearly the observed size with no ⁶Li in them whatever, and when the analyses were redone against those models the detections mostly evaporated.

The instructive part is what the false signal was made of. A model atmosphere with a missing physical effect does not fail loudly; it produces a residual, and a residual has to be attributed to something. The something available was an isotope with a plausible story attached. That is the same failure this collection describes in a planet that was the star’s own rotation — the same convective asymmetry, on the same kind of line, producing a different spurious object because a different object was being looked for.

Where the model stops

Nothing above rules the lithium problem solved or unsolvable, and it would be dishonest to imply a verdict the field has not reached. What the figures do is price the three routes against each other, and the prices are unequal in an instructive way: the particle-physics route is closed by a number that no model choice can move, the nuclear-rate route is closed by direct measurement, and the stellar route is not closed at all — it is merely uncomfortable, and it is uncomfortable about a second moment that carries an error bar of its own.

That last point deserves saying plainly, because it is where the argument here is weakest. The plateau’s scatter of 0.06 dex is an observed dispersion in a sample selected for being well-behaved, measured through a temperature scale that is itself uncertain. If the true intrinsic scatter were 0.10 dex rather than 0.06, the pricing above would loosen by a factor of nearly two and the steep destruction laws would come within sight of the required depletion. Nobody has measured the intrinsic scatter of the plateau to a precision that settles this, and doing so — rather than measuring more stars, or measuring them better — is what would actually move the subject.

Where this ladder goes next

The three light elements that agree do so because each carries the baryon density in a different way and each can be extrapolated back to its primordial value along a trend with a known direction. Deuterium only falls under processing; helium only rises. That one-sidedness is what makes the extrapolation legitimate, and it is not a property every light element has.

The next rung is the one that does not have it. Helium-3 is produced by low-mass stars out of the deuterium they swallow and destroyed by more massive ones, so the sign of the correction from what is observed to what was primordial changes with the mass of the star doing the processing — and there is consequently no quoted primordial ³He abundance anywhere in the literature. What survives is an inequality on the sum of deuterium and helium-3, which for most of the 1980s was the strongest statement anybody had about the density of ordinary matter in the universe.

Beyond that: inhomogeneous nucleosynthesis, and the convexity argument that says why a lumpy universe makes more lithium rather than less; and the neutron lifetime, whose two laboratory measurements disagree by ten seconds and whose disagreement propagates into every number on this ladder.

About the same objects

Not linked from either essay — found by the objects both name.

The objects this essay names

Each one links to every other essay that touches it.

Baryon-to-photon ratioBig bang nucleosynthesisConvective envelopeCross-sectionDeuterium abundanceElectron captureHalo starLithium problemMetallicityPrimordial abundanceRadiative captureSpite plateau