Cosmology

The residue that failed to burn

Deuterium's abundance is not a measure of what the first three minutes made. It is a measure of what escaped being used — a two-body destruction rate losing a race to a one-body expansion, which is why its curve against the baryon density is steep and helium's is flat.

Assumes Nucleosynthesis, Expansion and Line formation.

The first rung of this anchor put four abundances against one free parameter and inverted the steepest of them. Deuterium did the work: its curve falls as the baryon density rises, steeply enough that measuring D/H to a per cent measures the density to less than one, and the answer agrees with a sky map made four hundred thousand years later. The second rung took the flattest curve instead and got a particle count out of it.

Neither rung asked why the steep curve is steep. It was quoted as an exponent — D/H goes as η1.6\eta^{-1.6} — and an exponent lifted out of a fitting formula is a description of an answer rather than an account of it. The account is a race, and it is the same kind of race the previous rung ran between the weak interaction and the expansion, one epoch later and with the roles rearranged.

The deuterium burning rate against the expansion, at three baryon densities. The rate at which a deuteron is destroyed, divided by the expansion rate, against temperature. Temperature falls to the right, so the picture reads left to right as time, and the horizontal line at one is where the burning stops mattering: above it a deuteron is destroyed many times over before the universe doubles in size, below it the reaction has effectively ceased. The rate drawn is D(p,γ)³He at the NACRE parameterisation, multiplied by the free-proton density — three quarters of the baryons by number once ⁴He has taken the rest — and the expansion rate is the same 1.66√g* T²/mPl the freeze-out calculation raced the weak interactions against. The three curves differ in one number and one only: the baryons per photon, 3, 6, 12 in units of 10⁻¹⁰. They are therefore vertical translations of each other, exactly in proportion to η, because the reaction is two-body and the expansion is not. That is the entire mechanism by which an abundance measures a density. A denser universe crosses the line later — 21.4 keV at η₁₀ = 3, 16.0 keV at η₁₀ = 6, 12.3 keV at η₁₀ = 12 — and every extra second below the crossing is deuterium that does not survive. What the figure does not do is predict the abundance itself: the residue depends on the whole reaction network and on the ⁷Be and ³He channels that feed back into it, and the curve the abundance is read off is a fit to that network rather than to this.
Fig. 1 The rate at which a deuteron is destroyed, divided by the expansion rate, against temperature falling to the right. Above the line a deuteron is destroyed many times over before the universe doubles in size; below it the reaction has effectively stopped and what is left is what stays. The three curves differ in one number — the baryons per photon, 3, 6 and 12 in units of 10⁻¹⁰ — and they are exact vertical translations of each other, in proportion to η, because the destruction is a two-body reaction and the expansion is not. A denser universe crosses the line later, at 12.3 keV against 21.4, and every second below the crossing is deuterium that does not survive.

That figure is the mechanism. Everything below is an account of the three things it rests on: what deuterium is doing there at all, what a logarithmic slope is worth as a measurement, and what the two lines in a quasar spectrum that the abundance is actually read from look like.

Deuterium is the thing nothing wants to leave alone

The chain that makes helium has to pass through mass number two, and mass number two is the weakest link in it. A deuteron is bound by 2.2246 MeV, which is a tenth of what binds an alpha particle per nucleon and is small enough that the tail of a blackbody photon distribution can break it apart long after the mean photon energy has fallen well below it. With about a billion photons for every baryon, the tail is enormous: the previous rung’s bottleneck temperature of about 85 keV is roughly a twenty-sixth of the binding energy, and the factor of twenty-six is the logarithm of the photon-to-baryon ratio.

So deuterium is built late and burned fast. Once the photodissociation stops, the reactions that consume it run at rates set by nuclear physics rather than by the radiation field, and they run downhill: two deuterons make a tritium and a proton or a helium-3 and a neutron, and those in turn take another deuteron each and make an alpha. Six deuterons in and one alpha out, with the binding energy released at every step. The chain terminates at mass four because there is no stable nucleus at mass five and none at mass eight, so the network has nowhere to go and stops.

What is left over is a residue. Not a yield, not a product — the deuterium observed today is the fraction of the deuterium ever made that was never used, and the size of that fraction is set by how long the burning had before the universe pulled the reactants apart. The distinction matters because it inverts the intuition about what a denser universe does. More baryons do not mean more deuterium. More baryons mean more collisions, more burning, and less deuterium surviving, and the whole method rests on that sign.

It is worth being precise about how small the residue is, because the number is easy to read past. About two and a half deuterons survive per hundred thousand hydrogen nuclei. Essentially every nucleon in the universe passed through mass two on its way to mass four, so what is measured is a leak of a few parts in a hundred thousand from a process that was otherwise complete. A measurement of a residue at that level is only possible because the residue is stable: nothing destroys deuterium in the intergalactic medium, and the clouds the abundance is measured in have never been inside a star. Both of those conditions fail in the Galaxy, where the local interstellar D/H varies by a factor of three from sightline to sightline, mostly because deuterium sticks to dust grains.

The other reason a residue is a good thing to measure is that it is not a competition between two large numbers. The helium mass fraction is a quarter, and getting it to a per cent means predicting a number of order one to a per cent, with every systematic in the calculation contributing at that level. Deuterium’s abundance is fixed almost entirely by one thing — the integrated destruction — and a quantity that depends steeply on one input and hardly at all on the rest is exactly the kind of quantity a measurement can profitably invert.

A two-body rate against a one-body expansion

Every destruction channel available to a deuteron requires it to meet something. The rate per deuteron is therefore a number density times a cross section times a velocity, and the number density carries the baryon-to-photon ratio in it directly: at temperature T the photon density is fixed by the temperature alone, and the baryon density is η times it.

The expansion rate carries nothing of the kind. In the radiation era it is 1.66√g_* T²/mPl, and the energy density in that expression is radiation, which is photons and neutrinos and has no idea how many baryons are present. Baryons are a part in ten billion of it. So one side of the race scales with the density and the other side does not, and the ratio of the two — which is what decides whether a reaction is still doing anything — is exactly proportional to η at every temperature.

That is the mechanism in one sentence, and the drawn curves are its picture: three parallel lines separated by the logarithms of their densities. The reaction the figure draws is D(p,γ)³He, and the choice is deliberate rather than convenient. It is the channel that is first order in the deuterium abundance. The D + D channels are four orders of magnitude faster per pair, but their rate per deuteron carries a second factor of the deuterium abundance itself, and by the time the residue is being decided that abundance is ten parts in a million. A figure racing the D + D rate against the expansion would find the burning stopping before the deuterium had finished being made, which is wrong by about an hour.

The temperature dependence of the cross section is the Gamow factor and nothing else: two singly charged nuclei have to tunnel through each other’s Coulomb barrier, so the rate carries exp(−3(EG/4kT)^(1/3)) with EG = 0.979 MeV, and that exponential is what makes the crossing sharp. A rate falling as a power of temperature would leave the burning trailing off over decades of cooling; a rate falling as the exponential of an inverse cube root shuts off inside a factor of two.

Where the burning stops, and how long after the first three minutes. The same race read as a function of the baryon density. On the left, the temperature at which the destruction rate per deuteron falls below the expansion rate — from 29.33 keV at η₁₀ = 1.5 down to 10.37 keV at 19.2, because a denser universe keeps the reaction going to a lower temperature. On the right, the same crossing expressed as the age of the universe when it happens: 25 minutes at the low density and 204 at the high one. Both are radiation-era quantities, so the age is 1/2H exactly. The number worth carrying is that neither panel is steep: across a factor of 13 in density the freeze-in temperature moves as η^(−0.41), while the surviving deuterium moves as η^(−1.60). The abundance is not sensitive because the clock is sensitive; it is sensitive because the burning is exponential in how long it runs, and a small change in when it stops is a large change in what is left. The other thing the right-hand panel says is that the residue is not fixed in the first three minutes. Deuterium is made in the first three minutes and is still being destroyed an hour later, which is the part of this subject its own nickname hides.
Fig. 2 The same race read as a function of the density. On the left, the temperature at which the destruction rate falls below the expansion rate, dropping from 29.3 keV at η₁₀ = 1.5 to 10.4 keV at 19.2. On the right, the same crossing expressed as the age of the universe when it happens: 25 minutes at the low density and 204 at the high one. Neither panel is steep — across a factor of thirteen in density the freeze-in temperature moves as η0.41\eta^{-0.41} while the surviving deuterium moves as η1.60\eta^{-1.60}. The abundance is not sensitive because the clock is sensitive; it is sensitive because the burning is exponential in how long it runs.

The right-hand panel carries something the subject’s own nickname hides. Deuterium is made in the first three minutes, and it is still being destroyed an hour later. The reason the phrase survives is that the helium mass fraction — which is what the phrase was coined about — really is decided in the first few minutes, because it is twice a neutron fraction and the neutron fraction stops changing when the network fires. The deuterium residue is a different quantity with a different clock, and the two have been quoted in the same sentence for seventy years.

What a slope is worth

An abundance becomes a density by inversion, and inversion propagates a fractional error by the reciprocal of the logarithmic slope. If A(η) is the predicted abundance, then δη/η equals (δA/A) divided by the modulus of d ln A / d ln η. A steep curve shrinks the error; a flat one magnifies it into uselessness.

How much density each abundance is worth. The logarithmic slope d ln A / d ln η of each predicted abundance, measured by central difference on the same curves the abundances are read off rather than taken from the exponents in the fitting formulae. The slope is the exchange rate between a measurement and an inference: an abundance known to one per cent fixes the baryon density to one per cent divided by the modulus of this number. At the microwave background's density the four are ⁴He 0.04, D −1.60, ³He −0.60 and ⁷Li 2.00. Helium sits almost exactly on zero across the whole range, which is why it is drawn as a horizontal line in every abundance figure and why it counts neutrino species instead. Deuterium's −1.6 is the one the whole method rests on, and it is a statement about the reaction network: deuterium is the fragile intermediate every other product has to pass through, so raising the density burns more of it away. The uncomfortable line on the plot is lithium's, at 2.0: it is the steepest of the four, so ⁷Li would be the best baryometer in the set if its measured abundance agreed with its predicted one, and it is out by a factor of three.
Fig. 3 The logarithmic slope of each predicted abundance, measured by central difference on the same curves the abundances are read off rather than lifted from the exponents in the fitting formulae. At the microwave background’s density the four are ⁴He +0.04, D −1.60, ³He −0.60 and ⁷Li +2.00. Helium sits on zero across the whole range, which is why it counts neutrino species instead of baryons. The uncomfortable line is lithium’s: it is the steepest of the four, so ⁷Li would be the best baryometer in the set if its measured abundance agreed with its predicted one, and it is out by a factor of three.

Reading that figure the wrong way is easy and worth guarding against. It does not say that deuterium is measured well. It says that whatever deuterium is measured to, the density inherits five-eighths of the error, and that whatever helium is measured to, the density inherits twenty-five times it. The two statements are about the derivative of a curve and carry no information at all about how hard the observations are.

The slopes are also not free parameters, and each has a reason attached. Helium’s near-zero comes straight from the previous rung: the yield is twice a neutron fraction fixed by a weak-interaction rate, and the baryon density enters only through when the network fires, which is logarithmic. Deuterium’s steep negative slope is the burning. Helium-3’s shallower negative slope is the same burning acting on a nucleus with a higher Coulomb barrier, so it is destroyed less completely. Lithium’s positive slope of two is a production term rather than a destruction one — most of the mass-7 that survives is built as ⁷Be by ³He(α,γ)⁷Be, and that is a two-body reaction between two species whose abundances both rise with the density, hence the square.

Four curves, four exponents, and each exponent is a count of how many factors of the baryon density the dominant reaction carries. That is the structure the fitting formulae encode and it is the reason the exponents are close to whole and half numbers rather than arbitrary.

What each abundance's own error is worth as a density. The error bar each measured abundance carries, and the error bar it buys in the baryon density once it is inverted through the curve it sits on. The transfer is the reciprocal of the logarithmic slope: a fractional error δA/A becomes δη/η = (δA/A) ÷ |d ln A / d ln η|, so a steep curve shrinks the error and a flat one magnifies it. D / H is measured to 1.2 per cent and its slope is −1.60, giving 0.7 per cent in η; ⁴He is measured to 1.6 per cent and its slope is 0.04, giving 40.6 per cent in η; ⁷Li / H is measured to 19.0 per cent and its slope is 2.00, giving 9.5 per cent in η. The vertical rule is what the microwave background gets from the acoustic peaks, 0.7 per cent, from a completely different physics four hundred thousand years later. Two things are worth reading off this. Deuterium is the only light element whose abundance is a competitive measurement of the density, and the word is exact: it delivers 1.15 times the acoustic peaks' error rather than ten times it. The concordance between the two is a test precisely because neither is so much weaker than the other that agreement was guaranteed by the stronger one alone. And helium, measured to a percent and a half, delivers 41 per cent in η, which is not a measurement of anything: its flatness is what makes it a species counter instead.
Fig. 4 The error each abundance carries as measured, and the error it buys in the baryon density once inverted. Deuterium is measured to 1.2 per cent in a good absorption system and its slope of −1.60 turns that into 0.7 per cent in η. Helium is measured to 1.6 per cent and its slope of 0.04 turns that into 40.6 per cent, which is not a measurement of anything. The vertical rule is what the acoustic peaks give, also 0.7 per cent, from an entirely different physics four hundred thousand years later. The two are level, which is precisely what makes their agreement a test rather than a tautology.

The last sentence of that caption is the one that deserves an argument rather than an assertion. If two measurements agree and one of them is ten times more precise, the agreement is a statement about the precise one and the vague one is along for the ride. These two are within a few per cent of each other in precision, so either could have contradicted the other and neither is decorative. That is why the concordance between an absorption line at redshift three and the height of the second acoustic peak is quoted as evidence rather than as a consistency check.

Two lines, eighty-two kilometres a second apart

The measurement itself is not an abundance. It is a pair of absorption features in the spectrum of a quasar that happens to shine through a cloud of gas at high redshift, and the whole difficulty is in separating them.

Deuterium’s spectral lines sit at slightly shorter wavelengths than hydrogen’s, and the reason is entirely a reduced mass. The Rydberg constant for a one-electron atom carries μ = meM/(me + M), so a nucleus twice as heavy pulls the levels down by a part in 3,700. The shift is 2.75 parts in ten thousand, which at Lyman-α is 0.331 Å and in velocity units is 82 km/s, and it is the same 82 km/s at every line in the series because it is a fractional shift in wavelength.

The deuterium line, and what doubling the abundance does to it. A Lyβ absorption profile through a cloud with an H I column of 10^17.50 cm⁻² and a Doppler parameter of 12 km/s, computed as a Voigt profile from the oscillator strength 0.07912 and the damping constant 1.897e+8 s⁻¹. The deep feature is hydrogen. The shallow one 82 km/s to the blue is deuterium, and its offset is not fitted — it is the reduced-mass shift of the Rydberg constant between a proton and a deuteron, 2.72 parts in ten thousand, which at this wavelength is 0.279 Å. The two curves are the same cloud at D/H = 2.527e-5 and at 5.054e-5: the deuterium feature deepens from 23.7 to 40.8 per cent absorbed while the hydrogen line is untouched, because hydrogen's core is saturated and cannot get deeper. That asymmetry is the measurement's whole difficulty and its whole safeguard. The deuterium column comes off a line that is on the linear part of the curve of growth, so it is read almost directly; the hydrogen column has to come from somewhere else, either from a higher line in the series or from the damping wings, and the systematic that has sunk more than one published D/H is an unnoticed second hydrogen component at exactly −82 km/s masquerading as deuterium.
Fig. 5 A Lyman-β profile through a cloud with an H I column of 10^17.5 cm⁻², computed as a Voigt profile from the oscillator strength and the damping constant rather than sketched. The deep feature is hydrogen; the shallow one 82 km/s to the blue is deuterium, and its offset is not fitted. The two curves are the same cloud at D/H = 2.53 × 10⁻⁵ and at twice that: the deuterium feature deepens while the hydrogen line is untouched, because hydrogen’s core is saturated and cannot get deeper. That asymmetry is the measurement’s difficulty and its safeguard at once.

The deuterium feature is never saturated at the columns these systems have, so it reports its own column honestly; the trouble is all on the hydrogen side. A saturated line is a line whose depth has stopped responding to how much material is in front of it — the core has absorbed everything it can — and a hydrogen column measured from a saturated core is not measured at all. Ten times more hydrogen would look identical. This is the curve of growth in its least forgiving regime, and the standard escape from it is to stop looking at Lyman-α.

The Lyman series through one absorber, with the deuterium line 82 km/s to the blue. The same cloud seen in five successive lines of the Lyman series, at an H I column of 10^19.00 cm⁻², a Doppler parameter of 12 km/s and D/H = 2.527e-5. Velocity relative to the hydrogen line runs across each panel and the deuterium feature sits at −82 km/s in every one of them, because the isotope shift is a fixed fraction of the wavelength and therefore a fixed velocity. What changes down the series is the oscillator strength, which falls from 0.416 at Lyα to 0.0078 at Lyε — a factor of 53 — so the optical depth of both isotopes falls with it. That is the whole reason a measurement climbs the series. At Lyα the hydrogen core transmits 0.0e+0 of the light and its column is unmeasurable from the core: a factor of ten more hydrogen would look identical. At this column no line in the series comes off saturation, which is why the highest columns are measured from the damping wings instead. The deuterium feature is never saturated at these columns, so it is always giving its column honestly; the difficulty is entirely on the hydrogen side, and it is why the systems that produce a per-cent measurement are the ones with an H I column in a narrow window rather than the ones with the strongest absorption.
Fig. 6 The same cloud in five successive lines of the Lyman series at a higher column, 10^19 cm⁻². The deuterium feature sits at −82 km/s in every panel because the isotope shift is fractional in wavelength. What changes down the series is the oscillator strength, which falls by a factor of 53 from Lyman-α to Lyman-ε, and the optical depth of both isotopes falls with it. At Lyman-α the hydrogen core transmits nothing measurable; by Lyman-δ and Lyman-ε the hydrogen central optical depth has come down to where an equivalent width is a column density again. Climbing the series is not a refinement, it is the only route to the hydrogen number.

The two figures together explain why the usable systems are so few. A cloud with too little hydrogen has no detectable deuterium; a cloud with too much has a saturated deuterium line and the ratio becomes unreadable — above about 10^18.2 in H I column the deuterium feature stops responding to the abundance at all. The window between those bounds is roughly a decade wide, the cloud has to be metal-poor enough that its deuterium has not been processed by stars, it has to be at a redshift that puts the Lyman series into an optical spectrograph, and it has to sit in front of a quasar bright enough for a hundred-hour exposure to reach the required signal-to-noise. Rather more than a hundred thousand absorption systems are catalogued in the Lyman-α forest. Fewer than a dozen have produced a D/H measurement at the per-cent level.

The one parameter that decides whether the system is usable

The separation between the two lines is fixed by atomic physics. The width of them is not, and the width is what the measurement lives or dies on.

The deuterium feature disappearing into a hydrogen line that is too wide. The same Lyβ profile, at an H I column of 10^18.00 cm⁻² and D/H = 2.527e-5, drawn at three Doppler parameters: 8 km/s, 14 km/s, 25 km/s. Nothing about the gas changes except how fast its atoms are moving. At the narrowest the deuterium feature stands 65 per cent clear of the hydrogen wing beside it and the two are separate lines; at the widest it stands 1 per cent clear and is a shoulder on the hydrogen profile rather than a feature of its own. The separation between them is fixed at 82 km/s by atomic physics, so the only thing that decides whether the measurement is possible is a width — and the width is not known independently. It is fitted from the same profile the abundance is being read off, which is why the Doppler parameter and D/H are correlated in every one of these fits and why the quoted error is dominated by that correlation rather than by photon noise. The rule that follows is a selection rule rather than an analysis technique: a system with warm or turbulent gas is not measured more carefully, it is discarded.
Fig. 7 The same Lyman-β profile at three Doppler parameters — 8, 14 and 25 km/s — with nothing else changed. At the narrowest the deuterium feature stands 65 per cent clear of the hydrogen wing beside it and the two are separate lines; at the widest it is a shoulder on the hydrogen profile. The separation stays at 82 km/s throughout, because it is a fractional shift in wavelength and not a velocity anything is moving at. The width is fitted from the same profile the abundance is read off, so the two are correlated in every published fit, and the quoted error on D/H is dominated by that correlation rather than by photon noise.

This is why the field’s selection is so aggressive. A system with warm or turbulent gas is not analysed more carefully; it is discarded, because there is no amount of signal-to-noise that separates a deuterium feature from a hydrogen wing once the wing is wider than the isotope shift. Combined with the column-density window and the metallicity requirement, the selection removes better than 99.99 per cent of known absorption systems, and what survives is the sample that a per-cent measurement of the baryon density rests on.

Selecting that hard has an obvious risk attached, and the field states it rather than hides it: the systems chosen are chosen for a property — narrow lines, simple velocity structure — which is not obviously independent of the quantity being measured. The defence is that no plausible mechanism connects a cloud’s turbulence to its primordial deuterium, and that the measured values do not correlate with the selection variables. It is a defence rather than a proof, and it is the sort of argument the collection meets again wherever a sample is chosen by the thing that makes it measurable.

The failure mode that does not look like one

The systematic that has sunk more than one published deuterium abundance is not noise. It is a second, weaker cloud of ordinary hydrogen sitting by coincidence at −82 km/s relative to the main one, which produces an absorption feature indistinguishable from deuterium in a single line.

Nothing about the strength of that feature betrays it. Its width might, if the resolution is high enough: a hydrogen cloud has thermal motions of a given Doppler parameter and a deuterium feature in the same gas is narrower by √2, because the thermal width goes as the inverse square root of the mass. But a cold hydrogen interloper can be that narrow, and the discriminant is weak.

What actually settles it is the series. A real deuterium feature has to appear at −82 km/s in every Lyman line, with its own strengths scaling as the same oscillator strengths that scale the hydrogen lines, and with a column consistent across all of them. An interloping hydrogen cloud does the same thing — which is why the check works on something else: an interloper has its own higher-order Lyman lines whose ratios describe a hydrogen cloud rather than a deuterium one, and the two hypotheses part company once the column is high enough for the curve of growth to bend. The published measurements that were later withdrawn were withdrawn on exactly this, and it is why a modern paper reports the whole series rather than the ratio.

The other measurement of the same number

The reason any of this is worth doing at per-cent precision is that there is a completely independent route to the same quantity, and the two have no physics in common.

Baryons make the odd peaks taller. Three baryon densities, and what each does to the alternation between odd and even acoustic peaks. Baryons add inertia to the photon–baryon fluid without adding pressure, so it falls further into a gravitational well than it rebounds out of one: compressions are deeper than rarefactions, the odd-numbered peaks are compressions, and the ratio of the first peak to the second scales as (1 + 6R) with R = 3ρ_b/4ρ_γ at last scattering. At the measured Ω_b h² = 0.02237 that gives R = 0.622, and the drawn first-to-second ratios run 1.59, 2.26, 3.03 across Ω_b h² = 0.014, 0.02237, 0.032. Only that ratio is derived: the absolute heights come from the Planck measurement and the geometric mean of each adjacent pair is held fixed, because the envelope is set by radiation driving and photon diffusion, which no figure of this kind computes. What the alternation buys is a weighing of the ordinary matter in the universe from the shape of a sky map — a number that agrees, to better than a per cent, with the one deuterium gives.
Fig. 8 The angular power spectrum of the microwave background at three baryon densities, with everything else held fixed. Baryons load the photon–baryon fluid, and a loaded oscillator swings further one way than the other: compressions are deepened and rarefactions are not, so the odd-numbered acoustic peaks rise relative to the even-numbered ones. The ratio of the first peak to the second is therefore a baryon density, measured at four hundred thousand years by the geometry of a standing sound wave, and it agrees with a number obtained from a nuclear reaction network in the first hour.

Those two determinations share no equipment, no epoch, no physical process and no systematic. One is a nuclear cross section applied to a plasma at ten million kelvin, read off a spectrograph as the ratio of two absorption lines in a cloud twelve billion light years away. The other is the relative height of two bumps in the angular correlation function of a temperature map. They agree to a few per cent, and if the light-element abundances had come out wrong the disagreement would have been the most interesting result in the subject rather than a footnote.

What the picture cannot show

The burn-race figure draws the competition that decides when the deuterium stops being destroyed. It does not, and cannot, predict how much survives. That number is the output of a full reaction network — a dozen coupled species, forty-odd rates, and the ⁷Be channel feeding back through electron capture months later — and every abundance curve in this collection is a fit to such a network rather than to anything drawn here.

The gap between the two is instructive rather than embarrassing, because it is a specific gap with a specific size. A single two-body destruction channel racing a one-body expansion gives a residue exactly proportional to 1/η, an exponent of −1.00. The network gives −1.60. The missing 0.6 is the chain: deuterium is not only destroyed by protons, it is destroyed by the ³He and ³H that the D + D reactions have just produced, and those species have their own abundances that are themselves proportional to the baryon density. An effective destruction rate that carries the density more than once is steeper than one that carries it once, and that is the whole of the difference between the drawn slope and the real one.

The honest summary is that the figure explains the sign and the shape and hands the magnitude to a calculation it does not perform. That is a weaker claim than the picture might seem to make, and stating it is the only way the picture stays useful: a reader who took −1.6 to be derivable from three parallel lines would be wrong about the subject in a way nothing in the drawing would correct.

The shape of the argument, elsewhere

A quantity that survives a process is often a better measurement than a quantity the process produced, and the reason is always the same: what survives is exponential in how long the process ran, and an exponential is a lever.

The pattern recurs across this collection with no relationship between the physical settings. The neutron fraction left behind at freeze-out is a residue in exactly this sense, and it counts particle species because the expansion rate that ended the race carries the square root of their number. The white dwarf that has not yet cooled is a residue of a thermal reservoir, and its temperature is an age. In each case the measurable is small, is what escaped, and is steep in the parameter of interest — and in each case the quantity that was produced rather than left over turns out to be the flat one.

The corollary is the warning attached to all three. A residue is steep in the duration and therefore steep in everything that sets the duration, so an error in an input that is barely visible in a production yield is magnified in a leftover. Deuterium’s exponent of −1.6 is what makes it the baryometer, and it is also why the published network calculations disagree with each other by a per cent or two on the same input: the same steepness that turns a good abundance into a good density turns a small rate uncertainty into a visible one.

Where this ladder goes next

The concordance holds for three of the four species and fails for the fourth. Predicted ⁷Li at the density everything else agrees on is about three times what the oldest stars in the Galaxy show, the discrepancy has stood since the abundance was first measured in 1982, and it is the only place in this subject where a number that ought to be right is not.

The next rung is that failure, taken seriously rather than noted. It has exactly three kinds of resolution — the stars destroyed the lithium, the observation is measuring something else, or the network is missing something — and the datum that prices all three is not the plateau’s height but its flatness.

Beyond it: helium-3, and why an abundance that low-mass stars produce and massive ones destroy has no direction of correction and therefore no quoted primordial value at all; inhomogeneous nucleosynthesis, pursued for a decade as the one way to make the baryons account for all the matter, and the convexity argument that says why it aggravates the lithium problem instead of fixing anything; and the neutron lifetime, whose two laboratory measurements disagree by ten seconds and whose disagreement propagates into every number on this ladder.

What links here

Essays that link to this one from their own argument.

The objects this essay names

Each one links to every other essay that touches it.

Baryon densityBaryon-to-photon ratioBig bang nucleosynthesisColumn densityCurve of growthDeuterium abundanceDeuterium bottleneckFreeze outGamow peakIsotope shiftOscillator strengthQuasar absorption linesRadiative captureVoigt profile